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Determine k so that 4x^2-3x+k has one root which is twice...
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by
WinpossibleUser3626
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Determine k so that 4x^2-3x+k has one root which is twice the other root.
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Responses
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Given: 4x2 - 3x + k
The standard form of quadratic equation is ax2 + bx + c = 0
on comparing above equation a = 4, b = -3, and c = k
According to the given condition let y and z are the roots of the above equation. Then roots are
y = a and z = 2a
Now,
Sum of roots:
y + z = -b/a
a + 2a = -(-3)/4 = 3/4
3a = 3/4
a = 1/4
Products of the roots are
y*z = c/a = k/4
a * 2a = k/4
(1/4) * 2 (1/4) = k * (1/4)
k = 1/2
The value of k is ½
Related video lessons: Finding a Quadratic Equation given the roots ,
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by
Winpossible
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Aug 20, 10 07:02AM PST
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