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Find the eqquation of a line thats is perpendicular to th...
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by
WinpossibleUser3735
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Find the eqquation of a line thats is perpendicular to the line y=-x-5 and passes through the point-2,3. Please show steps if possible.
Thanks
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Responses
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Equation of a line is given by y = mx + c, where m is slope of the line and c is constant.
If we Compare this equation with the given line ( y = -x – 5 ) the slope of this line(m1) would be -1
=> m1 = -1
Now, if there are two lines with slope m1 and m2, then these two lines would be perpendicular to the each other only if
m1 * m2 = -1
So, using this property
Let us assume slope of a line perpendicular to line ( y = -x – 5 ) = m2
=> (-1) * (m2) = -1
=> m2 = 1
So the equation of a perpendicular line would be
y = x + c ….................Eq 1
As,this line passes through the point( -2, 3),so by putting these values in the equation 1
=> 3 = -2 + c
=> c = 3+2 = 5
Hence, the equation of the line perpendicular to y = -x – 5, which passes through ( -2, 3 ) is y = x + 5
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by
Winpossible
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Sep 07, 10 01:15PM PST
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