
Given the equation of the line is x  3y = 15
Converting it into the standard form we get,
y = x/3  5
so, we have a slope of the equation as 1/3.
the relation between two perpendicular lines is
m_{1} . m_{2} = 1
where m_{1}, m_{2} are slopes of two perpendicular lines.
therefore, 1/3 . m_{2} = 1
m_{2} = 3
So, the equation of the required line is
y = 3x  5
Related video links: Perpendicular Lines
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by
Winpossible

May 05, 10 07:06AM PST

