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Containing point (4, -1) is perpendicular to line x-2y = 6
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containing point (4, -1) is perpendicular to line x-2y = 6
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The equation of a line perpendicular to the given line is 2x + y = k, this line is passing through the given point (4, -1), So, 2(4)+(-1)= k. So k = 7, hence the required equation is 2x + y = 7.

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by Winpossible
Aug 26, 10 04:45AM PST
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