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Quadratic Equations: Miscellaneous Problem
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Quadratic Equations: Miscellaneous Problem
Example: the price of a book is reduced by $ 5, a person can buy 5 more books for $ 300. Find the original list price of the book.
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Solution: Let the original list price of the book be $ x
Number of books bought for $ 300 = 300/x 
     Reduced list price of the book = $(x - 5)
Number of books bought for $ 300 = 300/(x - 5)
     it is given that


1500/(x2 - 5x) = 5
x2 - 5x = 300
x2 - 5x - 300 = 0
(x - 20)(x + 15) = 0
x - 20 = 0 or, x + 15= 0
x = 20, x = -15
x = 20, x = -15 is not possible
Hence, the list price of the book = $ 20.
 
   
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