Algebra I: Factoring by grouping
This is a free lesson from our course in Algebra I
This lesson explains how to solve an equation using factoring by grouping. There are a few simple concepts to keep in mind while factoring a polynomial:
     when trying to factor a polynomial, first try to identify the GCF and divide every term of the polynomial by GCF. For example, 8x3 + 4x2 + 2x can be simplified into 2x(4x2 + 2x + 1).
Factor by grouping, is simply defined as the grouping of terms with common factors before factoring a polynomial. (More text below video...)
<h2> Factoring by grouping - Watch video (Algebra I)</h2> <p> factoring, factor, polynomial, equation, common, roots, quadratic, term, product, expression, variable, grouping, math help, parenthesis, binomial, practice questions, quizzes, solutions</p> <p> When trying to factor a polynomial, first try to identify the GCF and divide every term of the polynomial by GCF.</p>
Other useful lessons:
Solve 2nd order polynomial by factoring
Solving with the quadratic formula
Solution and discriminant in the quadratic formula
(Continued from above) A polynomial is a mathematical expression that is formed by variables and constants. The construction of such variables and constants is done by using operations of addition, subtraction, multiplication and non-negative whole number exponents
   in cases where there are four terms with no GCF, you should try factoring by grouping. First group the first two terms together and then the last two terms together and factor out a GCF from each seperate binomial, followed by factoring out the common binomial.
   in cases where there is no constant term in the polynomial, first factor out the variable and then factor the expression in the parenthesis into a product of binomials.
E.g. 9a3 15a2 + 3ba 5b
Solution: 9a3 15a2 + 3ba 5b
= (9a3 15a2) + (3ba 5b)
= 3a2(3a 5) + b(3a 5)
= (3a 5)(3a2 + b)
The explanation provided by our instructor in the video above will help you understand these concepts in an easier manner.
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