Algebra I: Solve 2nd order polynomial by factoring
This is a free lesson from our course in Algebra I
 
   
In this lesson, you'll learn the approach to simplifying a 2nd order polynomial by factoring. You'll see here how to write a polynomial equation in a standard form, use the zero factor property and solve polynomial equation by factoring. On solving the quadratic equation, you'll get the value of x. For example, x(14x - 15) = 9 gives two possible value of x, -3/7 and 3/2. To Factorize ax2 + bx + c steps are as follows:
using the leading coefficient of a you write the pair of incomplete factors.
multiply a and c, the coefficients of x2 and the constant term.
find integers whose product is a c and the constant term.
discard any common factor within each parenthesis in Step 3. The result is the desired factorization. (More text below video...)
<h2> Solve 2nd order polynomial by factoring - Watch video (Algebra I)</h2> <p> factoring, video, polynomial, quadratic, value, equation, online math, standard form, solve, online algebra, polynomials of second order, practice questions, solutions</p> <p> Write a polynomial equation in a standard form, use the zero factor property and solve polynomial equation by factoring.</p>
Other useful lessons:
Solving with the quadratic formula
Solution and discriminant in the quadratic formula
Factoring by grouping
(Continued from above) E.g. 6x2 + 7x 3
the lead coefficient is 6, so you write
(6x )(6x )
a c = (6)(- 3) = -18
two integers whose product is 18 and whose sum is 7 are 9 and 2. Then you write (6x + 9)(6x 2)
reducing (6x + 9) to (2x + 3) and (6x 2) to (3x 1) you have 6x2 + 7x 3 = (2x+3)(3x-1)
Once you go through the instructor's explanation in the video above, you'll be comfortable in dealing with second order polynomials.
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