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 Amsco Integrated Algebra I: Dividing Powers That Have the Same Base
This is a free lesson from our course in Amsco's Integrated Algebra
 
   
This lesson explains how to divide powers that have the same base. In order to do this find the exponent of the quotient, by subtracting the exponent of the divisor from the exponent of the dividend? The base of the quotient is the same as the base of the dividend and of the divisor. For example: x8÷x2=x(8-2)=x6 and 44/42 = 44-2 = 42.
Simply stating exponent rules for Quotient and Power are: Quotient: If you are required to divide the powers of the same base, subtract the exponents i.e. the top minus the bottom E.g. xa/xb = xa-b. Power: If you are required to find a power of a quotient, find the power of the numerator and the power of the denominator. (More text below video...)
<h2>>Adding and Subtracting Algebraic Expressions</h2> <p>term,like term,unlike term,monomial,polynomial,add,substract,algebra,solve algebra problem,video,quizzes</p> <p>explains about like and unlike terms and how to add and substract them.It also explains monomials and polynomials and how to add and substract them.</p>
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Adding and Subtracting Algebraic Expressions
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(Continued from above) E.g. (x/y)m = xm/ym
Remember: The exponent in each quotient is the difference between the exponent of the dividend and the exponent of the divisor E.g. If x ≠ 0 with a and b as positive integers and if a > b, then xa/xb = xa-b. The video below will explain in detail with the help of several examples.
 
   

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