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Amsco Integrated Algebra I: Using Inequalities to Solve
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This is a free lesson from our course in Amsco's Integrated Algebra
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This lesson explains, taking forward learning on basics and graphing of inequalities
in earlier lesson, how to solve problems using inequalities. A solution to any inequality
is any number that makes the inequality true. Many problems can be solved by writing
an equality that describes how the numbers in the problem are related and then solving
the inequality.
The inequalities also have principles dealing with addition and multiplication.
Take an illustration, in case of addition: if a > b then a + c > b + c. In
cases of multiplication: if a >b and c is positive, then ac > bc and if a
> b and c is negative, then ac < bc.
(More text below video...)
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People who saw this lesson also found the following lessons useful: |
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(Continued from above)
For example: The solution to inequality x + 4 > 8 is,
Using the addition principle, add -4 to each side of the inequality, which yields
x + 4 - 4 > 8 – 4. After simplification, the answer is x > 4.
Similarly to solve the inequality -4x < .8, multiply both sides by – 0.25, followed
by reversing the signs. It results: -0.25(-4x) > -0.25(.8) i.e. x > - 0.2
The video below will explain in detail with the help of several examples.
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