Amsco Integrated Algebra I: Using Inequalities to Solve Problems
 This is a free lesson from our course in Amsco's Integrated Algebra

 This lesson explains, taking forward learning on basics and graphing of inequalities in earlier lesson, how to solve problems using inequalities. A solution to any inequality is any number that makes the inequality true. Many problems can be solved by writing an equality that describes how the numbers in the problem are related and then solving the inequality. The inequalities also have principles dealing with addition and multiplication. Take an illustration, in case of addition: if a > b then a + c > b + c. In cases of multiplication: if a >b and c is positive, then ac > bc and if a > b and c is negative, then ac < bc. (More text below video...)
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 (Continued from above) For example: The solution to inequality x + 4 > 8 is, Using the addition principle, add -4 to each side of the inequality, which yields x + 4 - 4 > 8 – 4. After simplification, the answer is x > 4. Similarly to solve the inequality -4x < .8, multiply both sides by – 0.25, followed by reversing the signs. It results: -0.25(-4x) > -0.25(.8) i.e. x > - 0.2 The video below will explain in detail with the help of several examples.

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