|
|
|
|
|
|
|
Amsco Integrated Algebra I: Writing an Equation Given
the Intercepts |
|
This is a free lesson from our course in Amsco's Integrated Algebra
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
In this lesson you’ll learn how to write an equation given the intercepts. The
approach is simpler in this case. You know that with the y and x-intercept the two
coordinates are (0, y) and (x, 0). Now find the slope, by using m=y2-y1/x2-x1. Once
the slope is figured out; you can write the equation: y=mx+b, 'm' being the slope
and ‘b’ being the y-intercept. For example: if y-intercept= 5 and x-intercept= 3, write the equation. To solve
this steps are as given below:
• if the x-intercept is 3, one point is (3, 0).
(More text below video...)
|
|
|
|
|
|
|
|
|
|
|
|
People who saw this lesson also found the following lessons useful: |
|
|
|
|
|
|
|
|
|
(Continued from above)
• if the y-intercept is 5, one point is (0, 5).
• slope of the line from (3, 0) to (0, 5) = (0-5)/(3-0) = -5/3
• solve the resulting equation for y, it gives y = -5/3 x + 5
The equation for the given intercepts, equation is y = -5/3 x + 5, as the final
answer.
The video above explains more details on Writing an Equation Given the Intercepts,
with the help of several examples and their solutions.
|
|
|
|
|
|
|