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Area of Two Similar Triangles
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Area of Two Similar Triangles

Theorem: The ratio of the areas of two similar triangles is equal to the ratio of the sqaures of any two corresponding sides.
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Example: In two similar triangles ABC and PQR, if their corresponding altitudes AD and PS are in the ratio 3:7, find the ratio of the areas of ABC and PQR
Solution: Since the areas of two similar triangles are in the ratio of the squares of the corresponding altitudes.
Area (ABC) / Area of (PQR) = AD2/PS2
Area (ABC) / Area (PQR) = (3/7)2 = 9/49
Hence, Area (ABC): Area (PQR) = 9:49
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