This is a free lesson from our course in Geometry

 The Distance Formula In the coordinate plane, Pythagorean Theorem can be used to find the distance between two points. Let B(x1, y1) and A(x2, y2) be any two points in the coordinate plane. From A draw a vertical line and from B draw a horizontal line. Let the intersection of these two lines be C(x2, y1). Let AB = c, CB = a = |x2 - x1| and CA = b = |y2 - y1|.
(More text below video...)
People who saw this lesson also found the following lessons useful:
 Solving Right Triangles Pythagorean Theorem Converse
(Continued from above) Then,
c2 = a2 + b2
=> c2 = |x2 - x1|2 + |y2 - y1|2

This result is called the distance formula. If the endpoints of a line segment in the coordinate plane are B(x1, y1) and A(x2, y2), then:

 For example: in the coordinate plane, Pythagorean Theorem can be used to find the distance between two points. Say the distance between A (1, 2) and B (4, 6), (as indicated in Fig: 1): Notice thatABC is a right triangle, where AC = 3, And CB = 4. Use the Pythagorean Theorem now: AB2 = 32 + 42 i.e. AB2 = 25. Taking out the sq root, it gives AB = 5. It can be written in the general form, if (x1, x2) and (y1, y2) are two points in the coordinate plane; the distance between them is given by the formula as stated above:
Notice that if there are two points on a graph- say like (2, 3) and (2, 6), you can find the distance between them simply by counting units on the graph, as they lie in a vertical line on the graph. Similarly you can find the distance between the points simply by counting units on the graph, if they lie on a horizontal line.
The Pythagorean Theorem, which is used to find the hypotenuse of a right triangle, can also be used in three dimensions to find the diagonal length of a rectangular prism. Say D is the distance from one corner of the box to the farthest opposite corner, with a, b and c as length, width and height respectively,

But a more useful application of the Pythagorean Theorem in three dimensions is to find the distance between any two points in 'space'.

Look into some of the illustrative example below for sharpening the skills to help doing home work and solving real life examples related to Distance Formula.
Example 1: Given- find the distance between the points (4, 6) and (-2, 2).
You may use the formula
Step 1: (x1, x2) and (y1, y1) are two points i.e. (4, 6) and (-2, -2) respectively.
Step 2: Distance between the two points (D) = AB = simplify it,
=  (36 + 64) = 10
Distance between the two points is 10 units, as the final answer.
Example 2: Given- find the distance between the points (–3, –4) and (–5, 5).
Step 1: Plug in the values of coordinates in the distance formula.
Step 2:  D =
=  {(-5 + 3)2+ (5 + 4)2} = (4 + 81) = 85 = 9.2
Distance between the given points is 85 or 9.29 (rounded to first decimal), as the final answer.
Example 3: Given- You have a huge rectangular box with dimensions 8 ft. x 10 ft. x 16 ft. What is the length of the longest rod you could fit in the box? The box is of given dimensions is shown in figure below:
Notice that the longest rod you could fit in the box will have distance between A and D i.e. diagonal AD.
Step 1: To find AD, draw a right-angle triangle inside the box dimensions i.e. AD as its hypotenuse. Then apply Pythagorean Theorem.
Step 2: First find AC, which is the diagonal of rectangle.
Step 3: As ABC is a right angled triangle, so AC2 = AB2 + BC2 = 162 + (10)2 = 256 + 100 = 356.
Step 4: Then you can find AD i.e. AD2 = AC2 + CD2= 356 + 82 = 356 + 64 = 420
Taking sq root on both sides AD = 20.5 ft.
The longest rod you could fit in the box will be 20.5 ft, as the final answer.
Winpossible's online math courses and tutorials have gained rapidly popularity since their launch in 2008. Over 100,000 students have benefited from Winpossible's courses... these courses in conjunction with free unlimited homework help serve as a very effective math-tutor for our students.
 - All of the Winpossible math tutorials have been designed by top-notch instructors and offer a comprehensive and rigorous math review of that topic. - We guarantee that any student who studies with Winpossible, will get a firm grasp of the associated problem-solving techniques. Each course has our instructors providing step-by-step solutions to a wide variety of problems, completely demystifying the problem-solving process! - Winpossible courses have been used by students for help with homework and by homeschoolers. - Several teachers use Winpossible courses at schools as a supplement for in-class instruction. They also use our course structure to develop course worksheets.

 Copyright © Winpossible, 2010 - 2011 Best viewed in 1024x768 & IE 5.0 or later version