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Draw the sketch of the graph of the function and determin...
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by
WinpossibleUser3688
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draw the sketch of the graph of the function and determined the domain and range f={(x,y)|y=5-x2}
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Responses
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We have to make one assumption here that the equation you have provided is y = 5 – x^2 and you had some typographical error
Domain of this function :-
For a function f defined by an expression with variable x, the implied domain of f is the set of all real numbers variable x can take such that the expression defining the function is real.
So in this expression x can take any value for which y will have real no. so the domain of this function would be (- inf , + inf)
Range of a this function
The range of f is the set of all values that the function takes when x takes values in the domain. So in this expression if we put any value of x, this expression will give output of maximum +5 and minimum – inf because for any value of x, -x^2 will give either negative no. or zero. When -x^2 is zero it will give y = 5 and any other value it will give y < 5.
Hence the range of this expression is (-inf , 5]
For showing it on a graph we have to ta |
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by
Winpossible
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Aug 30, 10 09:47AM PST
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More to the Above Answer:
For showing it on a graph we have to take different set of points on a graph. This can be done by putting any value of one variable and then finding the value of other variable
e.g.
Point A: for x = 0, y = 5 => (0,5)
Point B: for x = +1, y = 4 => (1,4)
Point C: for x = -1, y = 4 => (-1, 4)
Point D: for x= +2, y = 1 => (2, 1)
Point E: for x= -2, y = 1 => (-2, 1)
So function y=5-x^2 passes through above mentioned 5 points and if we join these 5 points with free hand we will get the graphical representation of this function
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by
Winpossible
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Aug 30, 10 09:48AM PST
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